I read the article. Is there more to it than what shows up on the initial page? It seemed to leave me wanting a little more in depth information.

The author didn't go into how the added weight ratio was arrived at, or what (dynamic) component actually sees the result of the 10:1 ratio.

 

lol, i was thinking the same thing, i was like "thats it". I believe it was just a blog entry of some sort and not actually an article.

 

A 35 foot tire (35') is an awful big tire.

 

Answering the questions regarding torque of equally weight 33" and 35" wheel/tire.

Torque is the tendency of a force to rotate an object about an axis. It's based on Force applied, length of lever arm, and the angle between the force vector and lever arm.

Regarding Jeep wheel/tire combo (Using data from TireRack.com, Goodyear Wrangler MT/R Kevlar)

33x12.5R15 (60 lb) Steel wheel (28 lb) = 88 lbs
35x12.5R15 (67 lb) Alloy wheel (21 lb) = 88 lbs

Your taking away weight which is closer to the spinninig axis (wheel) and adding weight farther (tire tread weight + larger diameter).

This increases the torque needed to get the wheel tire spinning at equal speed.

 

just a little more info i found, seems to be some what connected to the blog entry.



http://www.jpmagazine.com/techarticl...n/viewall.html